Respuesta :
Answer:
(x - 2)² + (y - 4)² = 17
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
The centre is at the midpoint of the endpoints of the diameter, that is
x = [tex]\frac{6-2}{2}[/tex] = [tex]\frac{4}{2}[/tex] = 2 and y = [tex]\frac{5+3}{2}[/tex] = [tex]\frac{8}{2}[/tex] = 4
centre = (2, 4 )
The radius is the distance from the centre to either of the endpoints
Using the distance formula to find r
r = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (2, 4) and (x₂, y₂ ) = (- 2, 3)
r = [tex]\sqrt{(-2-2)^2+(3-4)^2}[/tex]
= [tex]\sqrt{(-4)^2+(-1)^2}[/tex]
= [tex]\sqrt{16+1}[/tex]
= [tex]\sqrt{17}[/tex] ⇒ r² = 17
Thus the equation of the circle is
(x - 2)² + (y - 4)² = 17
Answer:
D) (x − 2)2 + (y − 4)2 = 17
Step-by-step explanation:
The midpoint of the diameter is the center of the circle.
Endpoints of diameter: (6, 5) and (−2, 3)
6 −2/ 2 = 2; 5 + 3/2 = 4 → midpoint: (2, 4)
r = distance between center and either end point of the diameter
Distance formula: d = (x2 - x1)2 + (y2 - y1)2
center: (2, 4); point: (6, 5)
r = (6 − 2)2 + (5 − 4)2 → 16 + 1 → 17
(x − h)2 + (y − k)2 = r2 → (x − 2)2 + (y − 4)2 = 17