The concentration of a solution in which 75 g of C₁₂H₂₂O₁₁ are dissolved in 600. mL of water is 0.365M.
Concentration will be calculated in terms of molarity & it is defined as the number of moles of solute present in per liter of solution as:
M = n/V
Moles of C₁₂H₂₂O₁₁ = 75g / 342.3g/mol = 0.219 mol
Given volume = 600mL = 0.6L
On putting values, we get
M = 0.219/0.6 = 0.365M
Hence required concentration of solution is 0.365M.
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