niyahevette2004 niyahevette2004

05-04-2020
Mathematics

contestada

Find the total surface area of the right square pyramid with
a=1
h=2
Round to the nearest tenth.

Respuesta :

05-04-2020

Answer:

[tex]A

=

{a}^{2}

+

2a \sqrt{ \frac{ {a}^{2} }{4} + {h}^{2} }

\\

=

{1}^{2}

+

2

·

1

· \sqrt{ \frac{ {1}^{2} }{4}+ {2}^{2} }

\\

≈

5.12311[/tex]

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