Which equation is the inverse of the question
Answer:
y=± [tex]\sqrt{\frac{x+8}{2} }[/tex]
Step-by-step explanation:
y=2x^2-8
y+8=2x^2
x^2=(y+8)/2
x=±[tex]\sqrt{\frac{y+8}{2} }[/tex]
Substitute x=y, y=x
y=± [tex]\sqrt{\frac{x+8}{2} }[/tex]