The temperature of the gas will be "244.5 K".
Given values,
- Initial pressure, P₁ = 3.90 atm
- Final pressure, P₂ = 3.20 atm
- Initial temperature, T₁ = 298 K
- Final temperature, T₂ = ?
By using Gay-Lussac Law, we get
→ [tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]
By substituting the values,
[tex]\frac{3.90}{298} = \frac{3.20}{T_2}[/tex]
The temperature:
[tex]T_2 = 3.20\times \frac{298}{3.90}[/tex]
[tex]= \frac{953.6}{3.90}[/tex]
[tex]= 244.5 \ K[/tex]
Thus the above response is correct.
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