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A sample of 14 students was selected to estimate the average score in a given quiz. The average score in the sample is 2.14 with standard deviation of 1.29. Find a 99% confidence interval for the average score of the student in the class

Respuesta :

The average score of the student in the class at a 99% confidence lies between 1.252 and 3.028

Explanation:

Given values are

n = 14   = 2.14     σ = 1.29  z value for 99% confidence = 2.576

The mean is known one

= (z σ/√14)

=  (2.576 ×1.29÷√14)

[tex](2.576 ×1.29÷√14)[/tex]

= 2.576 × 0.345

= 0.888

 =  mean- 0.888 = 2.14  - 0.888 = 1.252

 =  mean+0.888 =  2.14 + 0.888 = 3.028

The average score of the students in the class at a 99% confidence lies between 1.252 and 3.028

Q&A Education