Answer:
The length of XK = 12.7
Step-by-step explanation:
Given that
JK = 12 , JL = 16 , KX = y + 3 , XL = 2y
From the Δ JKX
[tex]JX^{2} = JK^{2} - KX^{2} \\\\JX^{2} = 12^{2} - (y + 3^{2} )[/tex] ----- (1)
From the Δ JXL
[tex]JX^{2} = 16^{2} - (2y)^{2}[/tex] ---------- (2)
From Equation (1) & (2) we get
144 - ([tex]y^{2} + 9 + 6 y) =16 - 4 y^{2}[/tex]
[tex]3y^{2} -6y - 121 = 0[/tex]
By solving above equation we get
y = 9.7
Therefore the length of XK = y + 3 = 9.7 + 3 = 12.7
