Can someone please help me answer my last question?
[tex]f(x)=\frac{\sqrt{2x+8}}{x^{2}-2x }[/tex]

To find the domain of the function in the interval notation

Respuesta :

r3t40

Well we have a function and its body is a fraction so we need to handle those edge cases, namely division by 0.

That means solving the following equation,

[tex]x^2-2x=0\implies x(x-2)\implies x_1=0,x_2=2[/tex].

As we can see x must not be equal to 0 or 2 if we do not want to end up with division by zero situation.

The domain is therefore [tex]\mathbb{R}-\{0,2\}[/tex].

Writing this as interval would be,

[tex]x\in(-\infty,0)\cup(0,2)\cup(2,\infty)[/tex].

Hope this helps.

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