Lena is playing her accordion by compressing and stretching it. The accordion's length (in cm) t seconds
after it's completely stretched is modeled by A(t). Here, t is entered in radians.
A(t) = 25 cos (Tt) + 65
How long does it take Lena to compress the accordion completely and then stretch it back out to a length
of 50 cm?
Round your final answer to the nearest tenth of a second.

Respuesta :

Answer:

It takes Lena 4.1 seconds to compress the accordion completely and then stretch it back out to a length  of 50cm.

Step-by-step explanation:

I am assuming the function without a T: [tex]A(t)= 25cos(t)+65[/tex].

The function is graphed in the figure attached, and the blue line is [tex]y =50cm[/tex].

From the graph we see that the accordion is completely stretched  (has minimum length) at [tex]t= \pi[/tex] seconds, and stretches back  to 50cm at [tex]t=4.069s[/tex]; therefore, it takes Lena 4.069 seconds to stretch the accordion back again, which to the nearest tenth of a second is  4.1s

Ver imagen Poltergeist

Answer:

1.3 seconds

Step-by-step explanation:

Ver imagen sashaannargast
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