1. To increase the solubility of a gas at constant temperature from 0.85g/mL at 1.0atm to 5.1g/mL, the pressure would have to be increased to __________. *

Respuesta :

Answer : The pressure would have to be increased to 6.0 atm.

Explanation :

According top the Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas.

[tex]S\propto P[/tex]

or,

[tex]\frac{S_1}{S_2}=\frac{P_1}{P_2}[/tex]

where,

[tex]S_1[/tex] = initial solubility of gas = 0.85 g/mL

[tex]S_2[/tex] = final solubility of gas = 5.1 g/mL

[tex]P_1[/tex] = initial pressure of gas = 1.0 atm

[tex]P_2[/tex] = final pressure of gas = ?

Now put all the given values in the above formula, we get the final pressure of the gas.

[tex]\frac{0.85g/mL}{5.1g/mL}=\frac{1.0atm}{P_2}[/tex]

[tex]P_2=6.0atm[/tex]

Therefore, the pressure would have to be increased to 6.0 atm.

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