Answer:
[tex]Q = 301200\,J[/tex]
Explanation:
The energy required to heat water from its fussion point to its boiling point is the sum of latent and sensible heat. That is to say:
[tex]Q = m\cdot (L_{f}+c_{p,w}\cdot \Delta T + L_{v})[/tex]
[tex]Q = (100\,g)\cdot [334\,\frac{J}{g} +(4.18\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (100\,^{\textdegree}C)+2260\,\frac{J}{g} ][/tex]
[tex]Q = 301200\,J[/tex]
