Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0.

A. n = 32, n = 2 B. n = 6, n = 0 C. n = 1, n = 3 D. n = −2, n = −32

I find easier to use quadratic formula, ok? Let's go...

2n² - 7 n + 6 = 0, where the coefficients are: a = 2; b = -7 and c = 6.

[tex]n=\dfrac{-(-7)\pm \sqrt{(-7)^{2}-4.2.6}}{2.2}\rightarrow \\ n=\dfrac{7\pm 1}{4}\rightarrow n=\dfrac{3}{4}\,\,or\,\,n=2[/tex]

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micoarrafi micoarrafi · Answer 2 · 2016-07-05T23:10:16+02:00

micoarrafi micoarrafi

05-07-2016

Factoring in the quadratic equations

[tex]$\begin{align} 2n^2-7n+6&=0\\\frac12(2n-4)(2n-3)&=0\\(n-2)(2n-3)&=0\\n&=\boxed{2\ $or$\ \dfrac32} \end[/tex]

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Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0. A. n = 32, n = 2 B. n = 6, n = 0 C. n = 1, n = 3 D. n = −2, n = −32

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Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0.

A. n = 32, n = 2 B. n = 6, n = 0 C. n = 1, n = 3 D. n = −2, n = −32