Juarez scored 32 points in a basketball game. He scored twice as many baskets worth 3 points than baskets worth 2 points. How many baskets did he score worth 3 points and how many did he score worth 2 points?

Respuesta :

8, 3 pointers =24 points 4, 2 pointers = 8points 24+8= 34 points

Answer:

He scored 8 baskets worth 3 points and 4 baskets worth 2 points.

Step-by-step explanation:

Let Juarez scored x baskets worth 3 points and y baskets worth 2 points.

Thus, we have below equations.

[tex]3x+2y=32....(1)[/tex]

And the second equation is

[tex]x=2y[/tex]

From equation (1)

[tex]3(2y)+2y=32\\\\6y+2y\\32\\8y=32\\y=4[/tex]

Plugging this value in (1)

[tex]3x+2(4)=32\\3x=32-8\\3x=24\\x=8[/tex]

Hence, he scored 8 baskets worth 3 points and 4 baskets worth 2 points.

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