You have a bag containing 26 tiles, each imprinted with one letter of the alphabet. If you pick out 5 tiles, what is the probability that they are a, e, i, o, and u in that order?

For the first picking the probability of picking a is 1/26 as there is only 1 a out of the 26 letters. For the second picking there are only 25 letters and there is only 1 e out of the letters. For the succeeding picks, the probabilities are 1/24, 1/23, and 1/22. Thus, the probability is 1/7893600.

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facundo3141592 facundo3141592 · Answer 2 · 2022-06-01T17:01:38+02:00

Then the joint probability of getting "a", "e", "i", "o", and "u" in order, is P = 1.27*10⁻⁷

How to find the probability?

First, we need to get the letter "a", there is only one in the 26 tiles, so the probability is:

p₁ = 1/26

Then we need to get the "e", again there is only one, and we already drew the "a", so now there are 25 tiles left, then the probability is:

p₂ = 1/25.

For the next 3 letters, the probability will be:

p₃ = 1/24

p₄ = 1/23

p₅ = 1/22

Then the joint probability of getting "a", "e", "i", "o", and "u" in order, is:

P = (1/26)*(1/25)*(1/24)*(1/23)*(1/22) = 1.27*10⁻⁷

If you want to learn more about probability:

https://brainly.com/question/251701

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