li9lr0edheSilvirang
contestada

A leaky valve on the water meter overcharges the residents for one gallon of water every 1 1 over 3 months. The overcharged amount w varies directly with time t. Find the equation that models this direct variation. How many months it will take for the residents to be overcharged for 5 gallons of water? A) w = 3 over 4t; 62 over 3 months.B) w = 4 over 3t; 62 over 3 months. C) w = 3 over 4t; 33 over 4 months. D) w = 4 over 3t; 33 over 4 months

Respuesta :

taskmasters
The number of months overcharged for 1 gallon of leaky water = 1 1/3
                                                                                                     = 4/3
Let us assume the quantity of water overcharged = w
Let us assume the time in months = t
Then, the equation modelling this direct variation is
w = (3/4)t
When w = 5, then
5 = (3/4) * t
20 = 3t
t = 20/3
  = 6 2/3
From the above deduction, we can conclude that the first option or option "A" is the correct option. I hope the answer helps you.

Hagrid
The correct answer to this question is letter " A) w = 3 over 4t."
Given that the  number of months overcharged for 1 gallon of leaky water is equal to 1 1/3 and which is equal to 4/3.

Let w the quantity of water overcharged
Let t  the time in months

Let's make the equation. We have to use direct variation.
w = (3/4)t

w = 5, we will be able to get t
5 = (3/4) * t
20 = 3t
t = 20/3 = 6 2/3

Otras preguntas

Q&A Education