Respuesta :

apologiabiology
on the x axis means that the y value is 0
distance formula between 2 points (x1,y1) and (x2,y2)

D=[tex] \sqrt{(x1-x2)^{2}+(y1-y2)^{2}} [/tex]

D=5 and one point is (4,3) and the other is (x,0)
sub

5=[tex] \sqrt{(4-x)^{2}+(3-0)^{2}} [/tex]
5=[tex] \sqrt{(4-x)^{2}+(3)^{2}} [/tex]
square both sides
25=[tex] (4-x)^{2}+(3)^{2} [/tex]
25=[tex] (4-x)^{2}+9 [/tex]
minus 9 both sides
16=[tex] (4-x)^{2} [/tex]
square root both sides don't forget positive and negative roots
+/-4=4-x
minus 4 from both sides
-4+/-4=-x
times -1 both sides
4+/-4=x
4+4=x or 4-4=x
8 or 0=x



the possible points are
(0,0) or (8,0)
onyebuchinnaji

The points 5 units away from 4 is -1 to the left and 9 to the right. (-1, 9)

The given point:

[tex](x, y) = (4,3)[/tex]

To find:

  • all the points on x-axis 5 units away from the given points.

The points on x-axis 5 units away from the given points is calculated as:

[tex]x = +/- \ \ \ 5\\\\x_1 = -5 + 4= -1\\\\x_2 = +5 + 4 = 9[/tex]

Thus, the points 5 units away from 4 is -1 to the left and 9 to the right

Learn more here:https://brainly.com/question/16631417

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