Respuesta :
a.) Note that the maximum displacement is the amount the spring is pulled downwards which is 5 cm.
b.) The time required for one oscillation is the Period. You didn't specify it so we can't really say what it is.
c.) The frequency = 1/Period, i.e. frequency is the reciprocal of the Period. d.) Since the maximum displacement is 5 cm and the string was pulled downwards to start off with, the amplitude will be 5 and because it starts off downwards, we will have to make the 5 negative hence -5. The appropriate sinusoidal function to use in this case would be cosine. Now inside the brackets of cos( ) we will have 2pi/P, where P is the the period, multiplied by t, which is time. Hence the model is:f(t)=−5cos(2πPt)
b.) The time required for one oscillation is the Period. You didn't specify it so we can't really say what it is.
c.) The frequency = 1/Period, i.e. frequency is the reciprocal of the Period. d.) Since the maximum displacement is 5 cm and the string was pulled downwards to start off with, the amplitude will be 5 and because it starts off downwards, we will have to make the 5 negative hence -5. The appropriate sinusoidal function to use in this case would be cosine. Now inside the brackets of cos( ) we will have 2pi/P, where P is the the period, multiplied by t, which is time. Hence the model is:f(t)=−5cos(2πPt)
a.) The maximum displacement is when the spring is pulled downwards which is 5 cm.
b.) The time required for one oscillation is the Period. It is not specified in the problem so we cannot answer it.
c.) Frequency is the reciprocal of period.
d.) The maximum displacement is 5 cm and the string was pulled downwards initially, the amplitude will be 5 and because it is initially downwards, we will have -5. The appropriate sinusoidal function to use would be cosine. The model would be : f(t)=−5cos(2πPt)
b.) The time required for one oscillation is the Period. It is not specified in the problem so we cannot answer it.
c.) Frequency is the reciprocal of period.
d.) The maximum displacement is 5 cm and the string was pulled downwards initially, the amplitude will be 5 and because it is initially downwards, we will have -5. The appropriate sinusoidal function to use would be cosine. The model would be : f(t)=−5cos(2πPt)