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meerkat18
I saw the diagram.

m∠BXA = 30° 20'
m∠CXB = 40° 35'

m∠CXA = ?

m∠CXA = m∠BXA + m∠CXB
m∠CXA = 30° 20' + 40° 35'
m∠CXA = 70° 55'
calculista
the picture in the attached figure

we know that

m∠BXA = [tex]30[/tex]° [tex]20[/tex]'
m∠CXB = [tex]40[/tex]° [tex]35[/tex]'

m∠CXA = ?

m∠CXA = m∠BXA + m∠CXB
m∠CXA = [tex]30[/tex]° [tex]20[/tex]' + [tex]40[/tex]° [tex]35[/tex]'
m∠CXA = [tex]70[/tex]° [tex]55[/tex]'

therefore

the answer is
m∠CXA = [tex]70[/tex]° [tex]55[/tex]'
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