Respuesta :
The assumption in this answer is that the average mass of snowflake is 3 mg.
Answer:
112.5 kg
Explanation:
In 1 minute, there are 1250 snowflakes per square feet.
In 1 hour, there 1250 × 60 = 75000 snowflakes
1 snowflake has a mass of 3 mg
75000 snowflakes have a mass of 75000 × 3 = 225000 mg
Converting to kg
mass = 225000 ÷ (1000 × 1000) kg = 0.225 kg
This is the mass of snowflakes in 1 square feet.
The area of the lawn = 25.0 ft × 20.0 ft = 500 ft2
For 500 square feet,
mass = 0.225 kg × 500 = 112.5 kg
The question is incomplete! The complete question along with answer and explanation is provided below!
Question:
If your front lawn is 25.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1250 new snowflakes every minute, how much snow, in kilograms, accumulates on your lawn per hour? Assume an average snow flake has a mass of 1.70 mg.
Given Information:
Area of lawn = 25 ft into 20 ft = 500 ft²
Rate of snowflakes = 1250 per minute
Mass of snowflakes = 1.70 mg = 0.0017 g = 0.0000017 kg
Required Information:
Mass of snowflakes per hour = ?
Answer:
Mass of snowflakes = 63.75 kg
Explanation:
Total snowflakes = Rate of snowflakes*Area of lawn
Total snowflakes = 1250*500
Total snowflakes = 625000/min
Multiply by 60 minutes to convert into hour
Total snowflakes = 625000*60
Total snowflakes = 37500000/hour
Weight of snowflakes = Total snowflakes*Mass of each snowflake
Weight of snowflakes = 37500000*0.0000017
Weight of snowflakes = 63.75 kg
Therefore, there will be 63.75 kg of snowflakes in an area of 500 ft².
