Answer: [tex]sin 0^{\circ} = 0[/tex]
Step-by-step explanation:
Since, [tex]sin x = cos (90-x)[/tex] ( In first quadrant )
And, [tex]- sin x = cos (90+x)[/tex] ( In second quadrant )
Since, we have to find the value of [tex]sin 0^{\circ}[/tex]
And, we have [tex]cos 90^{\circ} = 0[/tex]
⇒ [tex]cos (90-0)^{\circ} = 0[/tex] or [tex]cos (90+0)^{\circ} = 0[/tex]
⇒ [tex]sin 0^{\circ} = 0[/tex] or [tex]-sin 0^{\circ}= 0[/tex] ⇒ [tex]sin 0^{\circ}= 0[/tex]
Thus, [tex]sin 0^{\circ} = 0[/tex]
