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A crate weighing 250 N is pulled up a 20° incline by a rope with a tension of 200 N. If the crate moves 5 m up the incline, what was the work done on the crate by the rope? (T remains constant throughout)

Respuesta :

Answer:

234.9 J

Explanation:

The total force acting on the rope are the downward weight of the crate and the upward tension acting on the string.

F = Wcos20 - Tcos20

F = 250cos20 - 200cos20

F = 46.98N

The total work done on the crate by the rope is:

W = F * d

W = 46.98 * 5

W = 234.9J

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