Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the newspapers did Ray deliver in the second hour?

Respuesta :

Answer:

[tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= [tex]\frac{3}{8}[/tex] of x

Total number of newspapers delivered in first hour= [tex]\frac{3}{8}[/tex]x

Number of newspapers left= x-[tex]\frac{3x}{8}[/tex]

Number of newspapers left=[tex]\frac{8x-3x}{8}[/tex]

Number of newspapers left=[tex]\frac{5x}{8}[/tex]

Number of newspapers delivered in second hour=4/5 of[tex]\frac{5x}{8}[/tex]

Number of newspapers delivered in second hour=[tex]\frac{x}{2}[/tex]

Fraction of newspapers delivered in second hour is=[tex]\frac{1}{2}[/tex]

Hence, the correct answer is [tex]\frac{1}{2}[/tex]

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