Answer:
The magnitude of the force on the charge is 4.0656 x 10⁻⁵ N
Explanation:
Given;
charge on the wire, q = 3.00-μC
speed of the charge, v = 4.40 x 10⁴ m/s
radius from the wire, r = 0.052 m
current in the wire, I = 80.0 A
F = qvB
from biot savart equation, we will determine strength of the magnetic field, B, produced by the current in the wire.
[tex]B = \frac{\mu _o I}{2\pi r} = \frac{4\pi *10^{-7} *80}{2\pi *0.052} =3.08 *10^{-4} \ T[/tex]
F = qvB = 3 x 10⁻⁶ x 4.4 x 10⁴ x 3.08 x 10⁻⁴ = 4.0656 x 10⁻⁵ N
Therefore, the magnitude of the force on the charge is 4.0656 x 10⁻⁵ N
