Answer:
So, exist 34650 different ways.
Step-by-step explanation:
We know that a group of 12 people is traveling in three vehicles. We know that 4 people ride in each vehicle.
So, for the first car we choose 4 people out of 12. Then from the remaining 8 people we choose 4 people for the second car. While the remaining 4 people will go into the third car.
Therefore, we get
[tex]C_4^{12}\cdot C_4^8\cdot C_4^4=\frac{12!}{4!(12-4)!}\cdot \frac{8!}{4!(8-4)!}\cdot 1=495\cdot 70=34650\\[/tex]
So, exist 34650 different ways.
