Answer:
Acceleration due to gravity on the surface of moon is given as
[tex]g = 1.62 m/s^2[/tex]
Explanation:
As we know that the acceleration due to gravity is given as
[tex]g = \frac{GM}{R^2}[/tex]
now we have
[tex]M = 7.35 \times 10^{22} kg[/tex]
[tex]R = 1.74 \times 10^6 m[/tex]
now we have
[tex]g = \frac{(6.67 \times 10^{-11})(7.35 \times 10^{22}}{(1.74 \times 10^6)^2}[/tex]
[tex]g = 1.62 m/s^2[/tex]
