Respuesta :
In 4 hours Bethany did the whole fraction 1 of the house.
In 1 hour he would do 1/4 of it.
In 3 hours Colin did the whole fraction 1 of the house.
In 1 hour he would do 1/3 of it.
In 1 hour they would both do (1/4 + 1/3)
If it takes both of them x hours to finish 1 whole fraction of the house.
In 1 hour they will both do 1/x
That means that:
1/x = 1/4 + 1/3
That is the equation. x can be solved for.
In 1 hour he would do 1/4 of it.
In 3 hours Colin did the whole fraction 1 of the house.
In 1 hour he would do 1/3 of it.
In 1 hour they would both do (1/4 + 1/3)
If it takes both of them x hours to finish 1 whole fraction of the house.
In 1 hour they will both do 1/x
That means that:
1/x = 1/4 + 1/3
That is the equation. x can be solved for.
Answer:
The equation is [tex]x=\frac{12}{7}[/tex]
Step-by-step explanation:
The amount of time it would take for Bethany and Colin to mow the lawn together = x
Bethany can mow her family’s lawn in 4 hours.
Let the mow work be m.
[tex]\texttt{Rate of Bethany}=\frac{m}{4}[/tex]
Colin can mow the lawn in 3 hour
[tex]\texttt{Rate of Colin}=\frac{m}{3}[/tex]
Time required when they mow together
[tex]x=\frac{m}{\frac{m}{4}+\frac{m}{3}}=\frac{12}{7}\\\\x=\frac{12}{7}[/tex]
The equation is [tex]x=\frac{12}{7}[/tex]