Answer:
Scores of 31.4 or higher are signicantly high.
Scores of 10.2 or lower are significantly low.
Step-by-step explanation:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 20.8, \sigma = 5.3[/tex]
Significantly high:
Scores of X when Z = 2 and higher. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]2 = \frac{X - 20.8}{5.3}[/tex]
[tex]X - 20.8 = 2*5.3[/tex]
[tex]X = 31.4[/tex]
Scores of 31.4 or higher are signicantly high.
Significantly low:
Scores of X when Z = -2 and lower. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-2 = \frac{X - 20.8}{5.3}[/tex]
[tex]X - 20.8 = -2*5.3[/tex]
[tex]X = 10.2[/tex]
Scores of 10.2 or lower are significantly low.