A rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s = 120t - 4t2 meters in t seconds. How high does the rock go? How long does it take the rock to reach its highest point?

Respuesta :

Answer:

Step-by-step explanation:

Given that a rock is thrown vertically upward from the surface of an airless planet. It reaches a height of [tex]s(t) = 120t - 4t^2[/tex]

where t is expressed in seconds

The rock goes upto a height where the velocity becomes 0 and then it starts falling down by gravity

Velocity at time t = s'(t) = [tex]120-8t[/tex]

This becomes 0 when t =15 seconds

Hence at 15th second the rock starts falling and upto

s(15) = [tex]120(15)-4(15^2)\\= 900[/tex] metres high it goes

The time taken to reach highest point is = 15 seconds.

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