Respuesta :

meerkat18
First, balance the number of carbon by multiplying CO2 by 5. Next, balance the hydrogen by multiplying 9/2 to H2O. The numbers of oxygen are already balanced from the given.
                                    C5H9O + O2 ---> 5CO2 + (9/2)H2O
To eliminate the fraction, multiply both sides by 2 giving,
                                   2C5H9O + 2O2 ---> 10CO2 + 9H2O
kenmyna

The complete balanced equation for the below reaction is

C5H9O + O2 yields CO2 +H2O

balanced equation

4 C5H9O + 27 O2 →20 CO2 +18 H2O

that is 4 moles of C5H9O reacted with 27 moles of O2 to yield 20 moles of CO2 and 18 moles of H2O. This reaction when balanced obey the law of mass conversion since the mass of the product is the same to the mass of the reactant.

kenmyna

The complete balanced equation for the below reaction is

C5H9O + O2 yields CO2 +H2O

balanced equation

4 C5H9O + 27 O2 →20 CO2 +18 H2O

that is 4 moles of C5H9O reacted with 27 moles of O2 to yield 20 moles of CO2 and 18 moles of H2O. This reaction when balanced obey the law of mass conversion since the mass of the product is the same to the mass of the reactant.

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