Answer:
Step-by-step explanation:
The time intervals are [0.00, 0.10], [0.10, 0.30], and [0.30, 0.60].
The rate of change in each interval is the slope of the line between the endpoints:
m = [f(b) − f(a)] / (b − a)
Filling out the table:
[tex]\left[\begin{array}{ccc}Time (s)&Height (ft)&Rate\ of\ change(ft/s)\\0.00&96.44\\&&\frac{97.60-96.44}{0.10-0.00}=11.6 \\0.10&97.60\\&&\frac{98.57-97.60}{0.30-0.10}=4.85\\0.30&98.57\\&&\frac{98.30-98.57}{0.60-0.30}=-0.90\\0.60&98.30\end{array}\right][/tex]
The intervals are already in order from greatest to least. Simply reverse the order to get least to greatest:
[0.30, 0.60]
[0.10, 0.30]
[0.00, 0.10]
Based on the information given, it should be noted that the average rate of change will be 11.6, 4.85, and -0.90.
From the information given, it should be noted that the time intervals have already been provided.
Therefore, the rate of changes will be:
= (97.60 - 96.44)/(0.10 - 0.00) = 11.6.
= (98.57 - 97.60)/(0.30 - 0.10) = 4.85
= (98.30 - 98.57)/(0.60 - 0.30) = -0.90
Therefore, the average rate of change will be 11.6, 4.85, and -0.90.
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