Respuesta :
To answer the question above, raise both sides of the equation to the power of two.
(sqrt (2x + 1))² = 3²
This will simplify into,
2x + 1 = 9
Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign.
(sqrt (2x + 1))² = 3²
This will simplify into,
2x + 1 = 9
Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign.
The value of x for the given equation is ±2.
What is Extraneous Solution?
An extraneous solution is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the problem.
Here, given equation is
[tex]\sqrt{2x^2+1}[/tex] = 3
On squaring both sides, we get
2x²+1 = 3²
2x² + 1 = 9
2x² = 8
x² = 4
x = ±2
Thus, the value of x for the given equation is ±2.
Learn more about extraneous solution from:
https://brainly.com/question/14054707
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