there are 28 members. If they must elect a​ chairperson, first vice​ chairperson, second vice​ chairperson, and​ secretary, how many different slates of candidates are​ possible?

Respuesta :

Answer:

491,400 different slates of candidates are​ possible

Step-by-step explanation:

The order is important.

For example, a slate of John, Rose, Laura and Elisa is different than a slate of Rose, John, Laura and Elisa, since the roles of John are Rose are exchanged.

Permutations formula:

The number of permutations of x elements from a set of n elements is given by:

[tex]P_{n,x} = \frac{n!}{(n-x)!}[/tex]

In this problem, we have that:

4 roles to be chosen from a set of 28 members. So

[tex]P_{28,4} = \frac{28!}{(28-4)!} = 491400[/tex]

491,400 different slates of candidates are​ possible

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