Assignment 6 – Spring 2020 1. A hotel claims that 90% of its customers are very satisfied with its service. Suppose that a random sample of eight customers is chosen. a. What is the probability that seven customers are very satisfied? [P(X = 7)]? Round to four decimal places. (3 points)

Respuesta :

Answer:

P(X = 7) = 0.3826

Step-by-step explanation:

We are given that a hotel claims that 90% of its customers are very satisfied with its service. A random sample of eight customers is chosen.

The Binomial probability distribution is given by;

[tex]P(X=r) = \binom{n}{r}p^{r}(1-p)^{n-r} , x = 0,1,2,3,...[/tex]

where, n = number of trials (samples) taken = 8

            r = number of success

            p = proportion of customers that are satisfied with hotel's service,

                   i.e.; p = 0.90

Let = Number of customers that are very satisfied

So, Probability that seven customers are very satisfied = P(X = 7)

     P(X = 7) = [tex]\binom{8}{7}0.9^{7}(1-0.9)^{8-7}[/tex]

                   = 8 * [tex]0.9^{7} * 0.1^{1}[/tex] = 0.3826

Therefore, probability that seven customers are very satisfied is 0.3826.

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