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Part A How many moles of NH3 can be produced from 13.5 mol of H2 and excess N2? Express your answer numerically in moles. View Available Hint(s) nothing mol NH3

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Eduard22sly

Answer:

9moles of NH3

Explanation:

First, we need to write a balanced equation for the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

From the equation,

3 moles of H2 produced 2moles of NH3.

Therefore, 13.5 mol of H2 will produce = (13.5 x 2)/3 = 9moles of NH3

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