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The 300 people who were lined up outside the amusement park had all entered by 8:15 a.m. By 8:30, 550 more had entered. The number who entered each 15 minutes increased steadily by 250 after that. All of the people were planning to stay for the parade at noon. a. How many people entered between 11:45 and noon, just in time for the parade ? b. Represent the problem as a series and write a formula for the nth term.

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TREKKER

Answer:

250; [tex]p= 300 + \frac{50}{3}t[/tex]

Step-by-step explanation:

a. 15 minutes passed, so there would be 250 people who came in

b. You would create a formula, where t = time after 8:15 (in minutes), while p = people who are at the parade

[tex]300 + \frac{250}{15}t = p[/tex], which equals [tex]p= 300 + \frac{50}{3}t[/tex]

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