In the diagram, TQ is 18 units in length. Line l is a perpendicular bisector of line segment R Q. It intersects line segment R Q at point T. Line l also contains point S. Line segment R T is 2 x + 10. Line segment S Q is 9 x minus 11. What is the length of RS? 16 units 18 units 25 units 46 units

Respuesta :

Answer:

[tex]RS=25\ units[/tex]

Step-by-step explanation:

we know that

If line I s a perpendicular bisector of line segment R Q at point T

then

T is the midpoint of line segment RQ

and

[tex]RT=TQ[/tex]

we have

[tex]TQ=18\ units[/tex]

so

[tex]RT=18\ units[/tex]

Find the value of x

we have

[tex]RT=2x+10[/tex]

substitute the value of RT

[tex]18=2x+10[/tex]

solve for x

[tex]2x=18-10\\2x=8\\x=4[/tex]

Find the value of SQ

[tex]SQ=9x-11[/tex]

substitute the value of x

[tex]SQ=9(4)-11=25\ units[/tex]

we have that

Triangle RTS and Triangle QTS are congruent  by SAS

see the attached figure to better understand the problem

so

[tex]RS=SQ[/tex]

therefore

[tex]RS=25\ units[/tex]

Ver imagen calculista
669173

Answer:

25

Step-by-step explanation:

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