Answer:
Molarity ZnCl2= 1.2 M
Explanation:
Step 1: Data given
Mass of zinc = 20.0 grams
Atomic mass of zinc = 65.38 g/mol
Volume = 255 mL = 0.255 L
Step 2: The balanced equation
Zn(s) + CuCl2(aq) → ZnCl2(aq) + Cu(s)
Step 3: Calculate moles Zn
Moles Zn = mass Zn / molar mass Zn
Moles Zn = 20.0 grams / 65.38 g/mol
Moles Zn = 0.306 moles
Step 4: Calculate moles ZnCl2
For 1 mol Zn we need 1 mol CuCl2 to produce 1 mol ZnCl2 and 1 mol Cu
For 0.306 moles Zn we have 0.306 moles ZnCl2
Step 5: Calculate molarity ZnCl2
Molarity = 0.306 moles / 0.255 L
Molarity ZnCl2= 1.2 M
