Answer:
(a) 330 ohm in series
(b) 8.866 ohm in parallel
series resistance is the sum of all individual resistance.
R=R1+R2+R3+...+Rn
R=3*45+3*65=330 ohm
now for parallel use relation
1/R=1/R1 + 1/R2 +1/R3 +1/Rn
1/R=1/45 + 1/45 + 1/45 + 1/65 + 1/65 1/65
R =8.866 ohm
(a) The total resistance of the circuit330 ohm in series
(b) The total resistance if all six are wired is = 8.866 ohm in parallel
In electronics, a circuit is refer to a closed path that allows electricity to flow from one point to another. Also, It may include various electrical components, such as transistors, resistors, and also capacitors, but they flow is unimpeded by a gap or break in the circuit.
(A) When the series resistance is the sum of all individual resistance.
Then, R=R1+R2+R3+...+Rn
Therefore, R=3*45+3*65=330 ohm
(B) Now, When the resistance if all six are wired in parallel use relation
After that, 1/R=1/R1 + 1/R2 +1/R3 +1/Rn
Then, 1/R=1/45 + 1/45 + 1/45 + 1/65 + 1/65 1/65
Thus, R =8.866 ohm
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