Answer:
4.433 kW
Explanation:
Suppose the flow rate is the same at the inlet and outlet at 57 m3/hr.
Since 1 hour = 60 minutes = 3600 seconds we can calculate the flowrate in m3/s
[tex]\dot{V} = 57 / 3600 = 0.0158 m^3/s[/tex]
As we are neglecting loss from friction and elevations changed, the power delivered by the pump is the product of the change in pressure and the flow rate
[tex]P = \Delta P \dot{V} = (400 - 120)*0.0158 = 4.433 kW[/tex]
