For the presented
problem, letβs say for the example (x^2-a^2)^2, the roots are only a and -a, but
it may be possible that theyβd count each root twice but can be prevented if
theyβre looking at the graph. You can actually make out two real zeroes and two
imaginary ones from the example. (x+1)(x-1)(x+i)(x-i) is (x^2-1)(x^2+1)= x^4-1.
I am hoping that this answer has satisfied your query about this
specific question.
