Answer: the concentration of C6H5 NH3+ = 0.031M
Explanation:
From question pH= 5.47
pH+pOH= 14
pOH= 14-5.47= 8.53
Using the Henderson Hasselbalch equation
pOH =pKb + log (salt/base)
8.53 = 9.13 + log(salt/0.125)
8.53-9.13= log(salt/0.125)
-0.6= log(salt/0.125)
Antilog (-0.6)=salt/0.125
0.251= salt/0.125
Salt conc.= 0.125×0.251=0.031M