Answer:
0.18
Step-by-step explanation:
The individual probabilities of each person eating the next fry must sum to 111. We know this because exactly one of the five people must eat each fry.
Hint #22 / 3
\begin{aligned}\text{P(M})+\text{P(R})+\text{P(L})+\text{P(A})+\text{P(C})&=1\\\\ 0.3+\text{P(R)}+0.1+0.32+0.1 &= 1 \\\\ \text{P(R)} &= 1-0.3-0.1-0.32-0.1 \\\\ \text{P(R)} & = \blueD{0.18} \end{aligned}
P(M)+P(R)+P(L)+P(A)+P(C)
0.3+P(R)+0.1+0.32+0.1
P(R)
P(R)
=1
=1
=1−0.3−0.1−0.32−0.1
=0.18
Hint #33 / 3
The probability that Ronald will eat the next fry is \blueD{0.18}0.18start color #11accd, 0, point, 18, end color #11accd.
Answer:
0.18
Step-by-step explanation:
The individual probabilities of each person eating the next fry must sum to 111. We know this because exactly one of the five people must eat each fry.
\begin{aligned}\text{P(M})+\text{P(R})+\text{P(L})+\text{P(A})+\text{P(C})&=1\\\\ 0.3+\text{P(R)}+0.1+0.32+0.1 &= 1 \\\\ \text{P(R)} &= 1-0.3-0.1-0.32-0.1 \\\\ \text{P(R)} & = \blueD{0.18} \end{aligned}
P(M)+P(R)+P(L)+P(A)+P(C)
0.3+P(R)+0.1+0.32+0.1
P(R)
P(R)
=1
=1
=1−0.3−0.1−0.32−0.1
=0.18
The probability that Ronald will eat the next fry is \blueD{0.18}0.18start color #11accd, 0, point, 18, end color #11accd.
