Answer:
Equation of the line: [tex]3y=x+10[/tex]
Step-by-step explanation:
If an equation of a line is perpendicular, its gradient will be such that: [tex]m_1 \times m_2 = -1[/tex]
Since the gradient /slope of the given equation can be inferred as -3, the gradient of the perpendicular line will be [tex]\frac{1}{3}[/tex].
Coordinates of a point on the line are (3,-1)
[tex](y-y_1) = m(x-x_1)\\\\(y-3) = \frac{1}{3} (x+1)\\\\3(y-3) = (x+1)\\3y -9= x+1\\3y = x+1+9\\3y = x+10[/tex]
