Answer:
F = mg/2
Explanation:
The full question is attached to the solution of this question.
The forces acting on the box include the weight of the box, the force, F and the tension in the wire attached.
The force required to pull up the box at constant velocity normally is equal to the weight of the box.
W = mg
But in this setup,
The force balance on the box
Sum of upward forces = sum of downward forces.
T + F = mg
But the pulley is frictionless, hence, the force, F is equal to the tension in the wire.
T = F
2F = mg
F = mg/2
Hope this Helps!!!
The magnitude F of the upward force should be F = mg/2
Here the force that should be acted on the box involved the weight of the box, force, and the tension where the wire should be attached.
W = mg
But in the given setup,
The force balance on the box
Sum of upward forces = sum of downward forces.
T + F = mg
Since the pulley is frictionless, so, the force, F is equal to the tension in the wire.
T = F
2F = mg
F = mg/2
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