Respuesta :
Answer:
29.5 m/s
Explanation:
Volumetric flowrate = (average velocity of flow) × (cross sectional area)
Volumetric flowrate = 0.111 liters/s = 0.000111 m³/s
Cross sectional Area of flow = πr²
Diameter = 0.00579 m,
Radius, r = d/2 = 0.002895 m
A = π(0.002895)² = 0.0000037629 m²
Velocity of flow = (volumetric flow rate)/(cross sectional Area of flow)
v = 0.000111/0.0000037629
v = 29.5 m/s
Given Information:
diameter of the nozzle = d = 5.79 mm = 0.00579 m
flow rate = 0.111 liters/sec
Required Information:
Velocity = v = ?
Answer:
Velocity = 4.21 m/s
Explanation:
As we know flow rate is given by
Flow rate = Velocity*Area of nozzle
Where
Area of nozzle = πr²
where
r = d/2
r = 0.00579/2
r = 0.002895 m
Area of nozzle = πr²
Area of nozzle = π(0.002895)²
Area of nozzle = 2.6329x10⁻⁵ m²
Velocity = Flow rate/area of nozzle
Divide the litters/s by 1000 to convert into m³/s
0.111/1000 = 1.11x10⁻⁴ m³/s
Velocity = 1.11x10⁻⁴/2.6329x10⁻⁵
Velocity = 4.21 m/s
Therefore, the water exit the nozzle at a speed of 4.21 m/s
