Find all solutions to 4tan(3x) = -4 between 0 and 360°. Give your answer in degrees.
Answer: the solutions are therefore 45 105 165 225 285 345
Step-by-step explanation:
Divide both sides by 4 to get
\tan(3x)=-1
Recalling the definition of tangent as ratio between sine and cosine, we have
\tan(3x)=-1 \iff \dfrac{\sin(3x)}{\cos(3x)}=-1 \iff \sin(3x)=-\cos(3x)
The sine and cosine of an angle are opposite only if the angle is
\alpha = 135+180k,\quad k \in \mathbb{Z}
So, we have
3x=135+180k \iff x = 45+60k,\quad k \in \mathbb{Z}
So, the solutions are
Answer: c) 45°, 105°, 165°, 225°, 285°, 345°
Step-by-step explanation:
4 tan (3x) = -4
tan (3x) = -1
tan⁻¹ [tan (3x)] = tan⁻¹ (-1)
Where on the Unit Circle does sin/cos = -1 → at 135° and 315°
All possible solutions are: 135° + 360n and 315° + 360n
:n = number of rotations
3x = 135 --> x = 45
3x = 315 --> x = 105
3x = 135 + 360 --> 3x = 495 --> x = 165
3x = 315 + 360 --> 3x = 675 --> x = 225
3x = 135 + 360(2) ---> 3x = 855 ---> x = 285
3x = 315 + 360(2) ---> 3x = 1035 ---> x = 345
Note that n = 3 results in x > 360 so these are the only valid solutions