I believe that the question refers to the picture in attachment.
We first calculate the length of every line with the Pythagoras' theorem and then we add it. (the lenghts are the differences bewteen the points on the lines)
I Will go from Q alphabetically and then back to Q:
[tex] \sqrt{4+25} [/tex]+[tex] \sqrt{4+16} [/tex]+[tex] \sqrt{4+9} [/tex]+[tex] \sqrt{1+16} [/tex]+[tex] \sqrt{64+9} [/tex]
For example, thing of the like QR as a part of a triagle QR(4,0)
I'll add them up
[tex] \sqrt{29} [/tex]+[tex] \sqrt{20} [/tex]+[tex] \sqrt{13} [/tex]+[tex] \sqrt{17} [/tex]+[tex] \sqrt{73} [/tex]
and calculate the roots (approximately)
[tex] \sqrt{29} [/tex]+[tex] \sqrt{20} [/tex]+[tex] \sqrt{13} [/tex]+[tex] \sqrt{17} [/tex]+[tex] \sqrt{73} [/tex]
5.38+4.24+3.60+4.4+8.54=5.38+7.84+12.94=13.22+12.94=26.16
so the best answer is b!
