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When Hiroto is writing, there is 0.92 probability that there will be no spelling mistakes on a page. One day, Hiroto writes an essay that is 11 pages long.
Assuming that Hiroto is equally likely to have a spelling mistake on each of the 11 pages, what is the probability that he will have a spelling mistake on at least one of the pages?

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MathPhys

Answer:

0.60

Step-by-step explanation:

Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

The probability of a mistake on at least one page is 1 minus the probability of making no mistakes.

P(at least 1) = 1 − P(none)

P = 1 − ₁₁C₀ (0.08)⁰ (0.92)¹¹⁻⁰

P = 1 − (0.92)¹¹

P = 0.60

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