Answer:
0.572 m
Explanation:
Assume that the ball is subjected to radial acceleration only and there's no tangential acceleration. Then the speed 23.7 m/s of the ball leaving her hand is the result of the centripetal acceleration a = 982 m/s2. We can use the following equation of motion to calculate the radius of motion, or her arm length:
[tex]a = \frac{v^2}{r}[/tex]
[tex]r = \frac{v^2}{a} = \frac{23.7^2}{982} = 0.572 m[/tex]
Answer:
length of her arm from the pivot point at her shoulder = 0.572m
Explanation:
Formula for radial acceleration = V²/r
From the question, radial acceleration = 982 m/s²
While speed(V) = 23.7m/s
And r is the radius of motion and in this case her arm is doing the motion, and thus r it's the length of her arm.
Thus; 982 = 23.7²/r
Making r the subject;
r = 23.7²/982 = 561.69/982 = 0.572m
