Answer:
3.298 K Hz
Explanation:
The Human ear canal can be attributed to a tube which is open at the end and closed at the other end. As shown in the figure attached the length of the canal is 2.6 cm representing L in the diagram.
To obtain our fundamental frequency the expression below is used;
f = v/λ ........................1
The length of the human ear canal is given as 2.6 cm and the speed of sound if not given is assumed to be 343 m/s
where f is the fundamental frequency;
v is the speed of sound = 343 m/s;
λ is the wavelength.
Calculating for the wavelength for the first harmonics using equation 2;
λ = 4 L.....................2
L is the length of the ear canal = 2.6 cm = [tex]\frac{2.6}{1000}[/tex] = 0.026 m
λ = 4 x 0.026 m
λ = 0.104 m
Now lets find the fundamental frequency using equation 1
f = v/λ ........................1
[tex]f = \frac{343 m/s}{0.104 m}[/tex]
f = 3298 Hz
f = 3298 Hz/1000
f = 3.298 K Hz
Therefore the fundamental frequency around which would expect the hearing to be more sensitive would be 3.298 K Hz
